Question

write a program in python to take year as input and check if it is a leap year or not.

Answer 1

Year=int (input("Enter year to be checked:"))
if(Year%4==0 and Year%100!=0 or Year%400==0):
print("The Year is a leap year!")
else:
print("The Year isn't a leap year!")

Answer 2

Answer:

# Python program to check if year is a leap year or not

year = 2000

# To get year (integer input) from the user

# year = int(input("Enter a year: "))

if (year % 4) == 0:

   if (year % 100) == 0:

        if (year % 400) == 0:

            print("{0} is a leap year".format(year))

      else:

          print("{0} is not a leap year".format(year))

  else:

      print("{0} is a leap year".format(year))

else:

  print("{0} is not a leap year".format(year))

Hope this helps you....⇔