Question

write a program input a list of no. and swap element at the even location with the element at the odd location​

Answer 1

Answer:

Suppose we have a list of numbers called nums, we will exchange each consecutive even indexes with each other, and also exchange each consecutive odd index with each other.

So, if the input is like [1,2,3,4,5,6,7,8,9], then the output will be [3, 4, 1, 2, 7, 8, 5, 6, 9]

To solve this, we will follow these steps −

length := size of nums

for i in range 0 to length, increase by 4, do

if i+2<length, then

exchange nums[i] and nums[i+2]

if i+3<length, then

exchange nums[i+1] and nums[i+3]

return nums

Let us see the following implementation to get better understanding −

Example

Live Demo

class Solution:

  def solve(self, nums):

     length = len(nums)

     for i in range(0,length,4):

        if(i+2<length):

           nums[i], nums[i+2] = nums[i+2], nums[i]

        if(i+3<length):

           nums[i+1], nums[i+3] = nums[i+3], nums[i+1]

     return nums

ob = Solution()

nums = [1,2,3,4,5,6,7,8,9]

print(ob.solve(nums))

Explanation:

hope this helps mark brainliest plz :-)