Question

write a program that calculates the root of a quadratic equation in c++ using pointers

Answer 1

Explanation:

#include(stdio.h)

#include(math.h)

void quadratic_roots(double *,double *, double *);

int main(void)

{

double a, b, c;

clrscr( );

printf("Enter the values of a,b and c :");

scanf("%lf %lf %lf", &a, &b, &c);

printf("\nThe required quadratic equation is : ax^2 + bx + c = 0");

printf("\nGiven Values: a = %lf \n b= %lf \n c= %lf ",a ,b, c);

quadratic_roots(&a,&b,&c);

getch( );

return 0;

}

void quadratic_roots(double *aa, double *bb, double *cc)

{

double root1, root2;

if((*bb)*(*bb)= = 4*(*aa)*(*cc))

{

root1= -(*bb)/2*(*aa);

printf("\nRoots are equal");

printf("\nvalue : %lf", root1);

}

else if((*bb)*(*bb) > 4*(*aa)*(*cc))

{

root1= (-(*bb) + sqrt((*bb)*(*bb) -(4*(*aa)*(*cc))))/(2*(*aa));

root2= (-(*bb) - sqrt((*bb)*(*bb) -(4*(*aa)*(*cc))))/(2*(*aa));

printf("\nThe roots of the equation are: %lf and %lf ", root1, root2);

}

else

{

printf("\nImaginary roots");

root1= (-(*bb) + sqrt((*bb)*(*bb) -(4*(*aa)*(*cc))))/(2*(*aa));

root2= (-(*bb) - sqrt((*bb)*(*bb) -(4*(*aa)*(*cc))))/(2*(*aa));

printf("roots are %f+i(%f) , %f-i(%f)",r1, r2, r1, r2);

}

}