Question

Write a program that divides two 1 bytes hex number where the dividend is stored in 4060H and divisor in 406H stored the quotient and remainder in next two consecutive memory location respectively.​

Answer 1

Program:

MOV AX , 0000H

MOV DS , AX  

MOV AL , [4060H]

MOV BL , [406H]

DIV BL

MOV [406H + 1] , AL

MOV [406H + 2] , AH  

HLT

Explanation:

MOV AX , 0000H ; load 0000H into AX register

MOV DS , AX  ; load DS register with the value of AX register

MOV AL , [4060H] ; load AL register with the value at memory location [4060H]. In AL we have stored the dividend.

MOV BL , [406H] ; load BL register with the value at memory location [4060H]. In BL we have stored the divisor.

DIV BL ; AL ÷ BL

MOV [406H + 1] , AL ; Store quotient

MOV [406H + 2] , AH ; Store remainder

HLT ; Exit