write a program that inputs an integer in range 0 to 999 and then prints if the integer entered is a 1 / 2 / 3 digit number
Answers
Answered by
21
Do I have to use Python3?
If yes, here is the code:
a=int(input("Enter a number: "))
if len(a)=1:
print(a)
elif len(a)=2:
print(a)
elif len(a)=3:
print(a)
You could put a else statement after this if you don't want an error:
else:
print("Not a 1, 2 or 3 digit number")
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Answered by
2
Answer:
public static void Main()
{
string number=Console.ReadLine();
if(number.Length==3)
{
Console.WriteLine("3 digit number");
}else if(number.Length==2){
Console.WriteLine("2 digit number");
}else if(number.Length==1){
Console.WriteLine("1 digit number");
}else{
Console.WriteLine("more than 3 digit number");
}
}
Explanation:
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