Write a program that inputs and integer in range 0-999 and then prints if the integer entered is a 1/2/3 digital number
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Answer:
Do I have to use Python3?
If yes, here is the code:
a=int(input("Enter a number: "))
if len(a)=1:
print(a)
elif len(a)=2:
print(a)
elif len(a)=3:
print(a)
You could put a else statement after this if you don't want an error:
else:
print("Not a 1, 2 or 3 digit number")
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