Write a program that inputs maximum 10 numbers but stops as soon as 4 even numbers are entered.
Answers
Answered by
6
Answer:
Explanation:
int arr[10],count=0;
for(int i=0;i<10;i++)
{
int num;
cout<<"enter a number";
cin>>num;
if(num%2==0)
count++;
if(count<4)
arr[i]=num;
else
break;
}
sswaraj04:
it's a general answer
use this logic for any language and complete according to it
you wrote the program in c++ dude we can say it by seeing your out and in statements
and already he liked the answer if you know better you are free to answer
if i can write the program in python it will be completed in 3 lines
sure, instead of reporting my answer if you have written your answer it wd be more helpful
but dev approved your program so cool..! did you see my report is deleted
yup bad luck dude!!
and he is not dev simply moderator
i don't want your answer to get deleted, i reported in mistakes in the answer and told there was no header that's it, i dont know it will be deleted even in mistakes in the answer option is given
Answered by
3
program in python:
for i in range ( 10 ):
num = int ( input ( "Enter a number : " ) )
if num == 4 : break
Explanation:
- first line of code says loop until the i value is less than 10
- default i value will be taken as 0 so the loop will iterate 10 times
- 2nd line input takes input from the user the int() method takes only the integer value, when you input a character or string it will show error
- 3rd line checks if the input num is equal to 4 or not, if true it breaks from the loop
- false the loop will again iterate by checking condition.
---Hope you understood my program. :)
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