write a program that inputs number of sides of a polygon and then determines whether it is a hexagon , a pentagon, a rectangle or a triangle
java
Answers
Answered by
24
import java.util.Scanner;
public class polygon
{
public static void main(String args[])
{
int poly_side;
System.out.print("No. of sides : ");
Scanner input=new Scanner(System.in);
poly_side=input.nextInt();
switch(poly_side)
{ case 3:
System.out.println("It is a Triangle");
break;
case 4:
System.out.println("It is a Rectangle");
break;
case 5:
System.out.println("It is a Pentagon");
break;
case 6:
System.out.println("It is a Hexagon");
break;
default:
System.out.println("Invalid Shape");
}
}
public class polygon
{
public static void main(String args[])
{
int poly_side;
System.out.print("No. of sides : ");
Scanner input=new Scanner(System.in);
poly_side=input.nextInt();
switch(poly_side)
{ case 3:
System.out.println("It is a Triangle");
break;
case 4:
System.out.println("It is a Rectangle");
break;
case 5:
System.out.println("It is a Pentagon");
break;
case 6:
System.out.println("It is a Hexagon");
break;
default:
System.out.println("Invalid Shape");
}
}
Answered by
0
Answer:
can someone rewrite this in c++
I'm sure I'll mark who answers correct as brainlest
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