write a program that inputs the number of sites of polygon and then determined whether it is hexagon, a Pentagon, a rectangle, or a triangle.
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We will learn how to find the sum of the interior angles of a polygon having n sides.
We know that if a polygon has ‘n’ sides, then it is divided into (n – 2) triangles.
We also know that, the sum of the angles of a triangle = 180°.
Therefore, the sum of the angles of (n – 2) triangles = 180 × (n – 2)
= 2 right angles × (n – 2)
= 2(n – 2) right angles
= (2n – 4) right angles
Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles.
Thus, each interior angle of the polygon = (2n – 4)/n right angles.
Now we will learn how to find the find the sum of interior angles of different polygons using the formula.
Name
Figure
Number of Sides
Sum of interior angles (2n - 4) right angles
Triangle

3
(2n - 4) right angles
= (2 × 3 - 4) × 90°
= (6 - 4) × 90°
= 2 × 90°
= 180°
Quadrilateral

4
(2n - 4) right angles
= (2 × 4 - 4) × 90°
= (8 - 4) × 90°
= 4 × 90°
= 360°
Pentagon

5
(2n - 4) right angles
= (2 × 5 - 4) × 90°
= (10 - 4) × 90°
= 6 × 90°
= 540°
Hexagon

6
(2n - 4) right angles
= (2 × 6 - 4) × 90°
= (12 - 4) × 90°
= 8 × 90°
= 720°
Heptagon

7
(2n - 4) right angles
= (2 × 7 - 4) × 90°
= (14 - 4) × 90°
= 10 × 90°
= 900°
Octagon

8
(2n - 4) right angles
= (2 × 8 - 4) × 90°
= (16 - 4) × 90°
= 12 × 90°
= 1080°
We know that if a polygon has ‘n’ sides, then it is divided into (n – 2) triangles.
We also know that, the sum of the angles of a triangle = 180°.
Therefore, the sum of the angles of (n – 2) triangles = 180 × (n – 2)
= 2 right angles × (n – 2)
= 2(n – 2) right angles
= (2n – 4) right angles
Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles.
Thus, each interior angle of the polygon = (2n – 4)/n right angles.
Now we will learn how to find the find the sum of interior angles of different polygons using the formula.
Name
Figure
Number of Sides
Sum of interior angles (2n - 4) right angles
Triangle

3
(2n - 4) right angles
= (2 × 3 - 4) × 90°
= (6 - 4) × 90°
= 2 × 90°
= 180°
Quadrilateral

4
(2n - 4) right angles
= (2 × 4 - 4) × 90°
= (8 - 4) × 90°
= 4 × 90°
= 360°
Pentagon

5
(2n - 4) right angles
= (2 × 5 - 4) × 90°
= (10 - 4) × 90°
= 6 × 90°
= 540°
Hexagon

6
(2n - 4) right angles
= (2 × 6 - 4) × 90°
= (12 - 4) × 90°
= 8 × 90°
= 720°
Heptagon

7
(2n - 4) right angles
= (2 × 7 - 4) × 90°
= (14 - 4) × 90°
= 10 × 90°
= 900°
Octagon

8
(2n - 4) right angles
= (2 × 8 - 4) × 90°
= (16 - 4) × 90°
= 12 × 90°
= 1080°
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