Question

Write a program to accept 10 number in a loop and print the count of all even number and count of all odd numbers

Answer 1

Answer:

#include <conio.h>

int main()

{

   int a[1000],i,n,even=0,odd=0;

   

   printf("Enter size of the array : ");

   scanf("%d",&n);

 

   printf("Enter elements in array : ");

   for(i=0; i<n; i++)

   {

       scanf("%d",&a[i]);

   }

 

    for(i=0; i<n; i++)

   {

         if(a[i]%2==0)

         even++;

         else

         odd++;

             

   }

    printf("even numbers in array: %d",even);

    printf("\n odd numbers in array: %d",odd);

 

   return 0;

}

Explanation:

 Enter size of the array: 5

 Enter elements in array: 1

2

3

4

5

even numbers in an array: 2

odd numbers in an array: 3