write a program to accept a number and check and diplay whether it is a spy number or not.(a number is a spy number if the sum of its digits equal the product of its digit)
example:consider the number 1124
sum of digits=1+1+2+4=8
product of digits =1*1*2*4=8
Answers
Explanation:
Co.de:-
#include <stdio.h>
#include <stdio.h>int main() {
#include <stdio.h>int main() { int num, i;
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: ");
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num);
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num); printf("Factors of %d are: ", num);
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num); printf("Factors of %d are: ", num); for (i = 1; i <= num; ++i) {
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num); printf("Factors of %d are: ", num); for (i = 1; i <= num; ++i) { if (num % i == 0) {
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num); printf("Factors of %d are: ", num); for (i = 1; i <= num; ++i) { if (num % i == 0) { printf("%d ", i);
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num); printf("Factors of %d are: ", num); for (i = 1; i <= num; ++i) { if (num % i == 0) { printf("%d ", i); }
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num); printf("Factors of %d are: ", num); for (i = 1; i <= num; ++i) { if (num % i == 0) { printf("%d ", i); } }
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num); printf("Factors of %d are: ", num); for (i = 1; i <= num; ++i) { if (num % i == 0) { printf("%d ", i); } } return 0;
#include <stdio.h>int main() { int num, i; printf("Enter a positive integer: "); scanf("%d", &num); printf("Factors of %d are: ", num); for (i = 1; i <= num; ++i) { if (num % i == 0) { printf("%d ", i); } } return 0;}