Question

Write a program to accept a number more than one digit. Then find the sum of all odd digit and product of all even digit.

Urgent Please!!!!!!!!!

Correct Answer I want!!!!!???????​

Answer 1

Answer:

odd numbers =n² even no.=n(n+1)

Answer 2

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 System.out.print("Enter a number:");

 Scanner sc = new Scanner(System.in);

 int n = sc.nextInt();

 int temp = n , evenDigitSum = 0 , oddDigitProduct = 1;  

     while(temp!=0){

         int r = temp%10;

             if(r%2 == 0){

                 evenDigitSum = evenDigitSum + r;

             }

             if(r%2 == 1){

                 oddDigitProduct = oddDigitProduct * r;

             }

             temp/=10;

     }

    System.out.println("The sum of all even digits in " + n + " is " + evenDigitSum);

    System.out.println("The product of all odd numbers in " + n + " is " + oddDigitProduct);

}

}

Explanation: