Question

Write a program to accept any 10 numbers. Display the sum of only
the negative numbers.​

Answer 1

Answer:

#include<stdio.h>

int main()

{

    int number, i, sum=0;

    for(i=0;i<=10;i++)

    {

        printf("Enter number: ");

        scanf("%d",&number);

        if( number<0 ) //-ve numbers are skipped

            continue;

        sum += number; //sum = sum + number

    }

    printf("Sum=%d",sum);

    return 0;

}

Step-by-step explanation:

Answer 2

Answer:

Pictorial Presentation:

Read 10 numbers and find their sum and average

Sample Solution:

C Code:

#include <stdio.h>

void main()

{

int i,n,sum=0;

float avg;

printf("Input the 10 numbers : \n");

for (i=1;i<=10;i++)

{

printf("Number-%d :",i);

scanf("%d",&n);

sum +=n;

}

avg=sum/10.0;

printf("The sum of 10 no is : %d\nThe Average is : %f\n",sum,avg);

}

Copy

Sample Output:

Input the 10 numbers :

Number-1 :1

Number-2 :2

Number-3 :3

Number-4 :4

Number-5 :5

Number-6 :6

Number-7 :7

Number-8 :8

Number-9 :9

Number-10 :10

The sum of 10 no is : 55

The Average is : 5.500000

Flowchart:

Flowchart: Read 10 numbers and find their sum and average

C Programming Code Editor:

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Previous: Write a program in C to display n terms of natural number and their sum.

Step-by-step explanation:

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