Question

write a program to accept any number from user and search it in a list of values, if number is found then display a message "number found"​ other wise display a message number not found​

Answer 1

Answer:

Input: arr[] = {10, 5, 3, 4, 3, 5, 6}

Output: 5 [5 is the first element that repeats]

Input: arr[] = {6, 10, 5, 4, 9, 120, 4, 6, 10}

Output: 6 [6 is the first element that repeats]

Answer 2

Answer:

number=int(input("Enter number:"))

numlist=[2,5,8,1,3,9,12,45] #if it is given just #replace the numbers

l=len(numlist)

flag=0

for i in range (0,l):

if number==numlist [i]:

#print ("number found")

flag+=1

#break

if flag==0:

print ("number not found")

else:

print ("number found") # flag times #occurence--->

#print("number found",flag,"times")

#hope it will work