Computer Science, asked by lk1815241, 3 months ago

Write a program to accept strings as command line argument and print the number of arguments entered.

Sample Input (Command Line Argument) 1:
Command Arguments

Sample Output 1:
Arguments :
Command
Arguments
Number of arguments is 2

Sample Input (Command Line Argument) 1:
Commands

Sample Output 2:
Arguments :
Commands
Number of arguments is 1

Answers

Answered by khanazmat12344
5

Answer:

#include <stdio.h>

void main(int argc, char *argv[] ) {

printf("Program name is: %s\n", argv[0]);

if(argc < 2){

printf("No argument passed through command line.\n");

}

else{

printf("First argument is: %s\n", argv[1]);

}

}

Answered by Shamsessa123
0

ANSWER:

java program:-

class simple

{

public static void main(String args[])

int n1,n2;

n1=args[0];

n2=args[2];

System.out.println("Arguments:"+n1+" "+n2);

System.out.println("Number of Arguments:"+count(args));

}

output:-

>>javac simple.java

>>java simple Command Arguments

Explanation:

for accepting input as string use : args[0]

for integer use : Integer.parseInt(args[0])

for boolean use : Boolean.parseBoolean(args[0])

for compiling java program : type & save java progarm using .java extension then type in command prompt >>javac simple.java

for executing java program >>java simple "str"

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