Question

Write a program to calculate the sum of digit of a three digit number

Answer 1

If it's question from java then the answer is the following :-

public class

{

public void main(int a)

{

int temp = a;

int sum = 0;

while (temp > 0)

{

int d = temp % 10;

sum = sum + d;

temp = temp / 10;

}

System.out.println(sum);

}

}

.

.

.

Please use the codings as I have done , no digits or symbols should be changed in order to get correct output.

Answer 2

Program to calculate the sum of digit of a three digit number.

#include <stdio.h>

int main()

{

int n, t, sum = 0, remainder;

printf("Enter an integer\n");

scanf("%d", &n);

t = n;

while (t != 0)

{

remainder = t % 10;

sum = sum + remainder;

t = t / 10;

}

printf("Sum of digits of %d = %d\n", n, sum);

return 0;

}

Explanation:

I have Given the C program to Calculate Sun of 3 digit numbers. We know that, At stating of C program, we write '#include <stdio.h>'

So, we write '#include <stdio.h>' at the starting. After that:

int main()

{

int n, t, sum = 0, remainder;

We will have to write Sum = 0. Because we have to find sum of three digit number.

Then, write:

while (t != 0)

{

remainder = t % 10;

sum = sum + remainder;

t = t / 10;

}

Now, Main point. It is Printf. write Printf code after the given program:

printf("Sum of digits of %d = %d\n", n, sum);

return 0;

}

▪️ Here is a program for without Modulus operator:

#include <stdio.h>

int main()

{

int c, sum, t;

char n[1000];

printf("Input an integer\n");

scanf("%s", n);

sum = c = 0;

while (n[c] != '\0') {

t = n[c] - '0'; // Converting character to integer

sum = sum + t;

c++;

}

printf("Sum of digits of %s = %d\n", n, sum);

return 0;

}