Computer Science, asked by ritik632473, 1 year ago

write a program to check magic number or not

Answers

Answered by soubhik
2
Here is the code required for the above

program in


PYTHON3 :



def isMagic(n):

    sum = 0;

      

    # Note that the loop 

    # continues if n is 0 

    # and sum is non-zero.

    # It stops when n becomes 

    # 0 and sum becomes single

    # digit.

    while (n > 0 or sum > 9):

        if (n == 0):

            n = sum;

            sum = 0;

        sum = sum + n % 10;

        n = int(n / 10);

          

    # Return true if sum becomes 1.


     return True if (sum == 1) else False;

  

# Driver code

n = 1234;

if (isMagic(n)):

    print("Magic Number");

else:

    print("Not a magic Number");


Check if it runs properly ;-)


Answered by Anonymous
4

Answer:

import java.util.*;

class magic_number

{

   public void main()

   {

       Scanner sc=new Scanner(System.in);

       System.out.println("Enter a number to check whether it is a magic number or not");

       int n=sc.nextInt();

       int d=0;

       int s=n;

       while(s>9)

       {

           n=s;

           s=0;

           while(n>0)

           {

               d=n%10;

               s=s+d;

               n=n/10;

           }

       }

       if(s==1)

       {

           System.out.println("Magic number");

       }

       else

       {

           System.out.println("Not a magic number");

       }

   }

}

Explanation:

We can check magic number by running two while loops .

Note that we have to swap the values of 's' and 'n' .

Then if s<9 loop ends .

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