Write a program to check whether a number input by the user is Armstrong number or not.
Answers
in c, c++
#include <stdio.h>
int main()
{
int number, originalNumber, remainder, result = 0;
printf("Enter a three digit integer: ");
scanf("%d", &number);
originalNumber = number;
while (originalNumber != 0)
{
remainder = originalNumber%10;
result += remainder*remainder*remainder;
originalNumber /= 10;
}
if(result == number)
printf("%d is an Armstrong number.",number);
else
printf("%d is not an Armstrong number.",number);
return 0;
}
An Armstrong number is a number whose sum of cubes of digits is equal to the number itself.
For example:
153 = 1³+5³+3³
1+125+27
=153
Program:
import java. util.*;
class Armstrong
{
public static void main (string args [])
{
Scanner sc = new Scanner
int n, r, p, s=0, m;
System.out.println ("Enter a number");
n=sc.nextInt();
while
{
r=n%10
p=r*r*r;
s=s+p;
n=n/10;
}
if (m==s)
System.out.println (m+"is Armstrong");
else
System.out.println (m+"is not Armstrong");
}
}