Question

write a program to check whether a number is equilibrium or not

Answer 1

✪Hey There✪


#include <stdio.h>

 

int equilibrium(int arr[], int n)

{

  int i, j;

  int leftsum, rightsum;

 

  /* Check for indexes one by one until an equilibrium

    index is found */

  for ( i = 0; i < n; ++i)

  {

    leftsum = 0;  // initialize left sum for current index i

    rightsum = 0; // initialize right sum for current index i

 

    /* get left sum */

    for ( j = 0; j < i; j++)

      leftsum  += arr[j];

 

    /* get right sum */

    for( j = i+1; j < n; j++)

      rightsum += arr[j];

 

    /* if leftsum and rightsum are same, then we are done */

    if (leftsum == rightsum)

      return i;

    }

 

  /* return -1 if no equilibrium index is found */

  return -1;

}

 

int main()

{

  int arr[] = {-7, 1, 5, 2, -4, 3, 0};

  int arr_size = sizeof(arr)/sizeof(arr[0]);

  printf("%dn", equilibrium(arr, arr_size));

 

  getchar();

  return 0;

}