write a program to check whether a short type number taken as input is an even number or an odd number
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Good morning aaj busy rahungi sorry
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To understand this example, you should have the knowledge of following C programming topics:
An even number is an integer that is exactly divisible by 2. Example: 0, 8, -24
An odd number is an integer that is not exactly divisible by 2. Example: 1, 7, -11, 15
Example #1: Program to Check Even or Odd
#include <stdio.h> int main() { int number; printf("Enter an integer: "); scanf("%d", &number); // True if the number is perfectly divisible by 2 if(number % 2 == 0) printf("%d is even.", number); else printf("%d is odd.", number); return 0; }
Output
Enter an integer: -7 -7 is odd.
In the program, integer entered by the user is stored in variable number
Then, whether the number is perfectly divisible by 2 or not is checked using modulus operator.
If the number is perfectly divisible by 2, test expression number%2 == 0 evaluates to 1 (true) and the number is even.
However, if the test expression evaluates to 0 (false), the number is odd.
An even number is an integer that is exactly divisible by 2. Example: 0, 8, -24
An odd number is an integer that is not exactly divisible by 2. Example: 1, 7, -11, 15
Example #1: Program to Check Even or Odd
#include <stdio.h> int main() { int number; printf("Enter an integer: "); scanf("%d", &number); // True if the number is perfectly divisible by 2 if(number % 2 == 0) printf("%d is even.", number); else printf("%d is odd.", number); return 0; }
Output
Enter an integer: -7 -7 is odd.
In the program, integer entered by the user is stored in variable number
Then, whether the number is perfectly divisible by 2 or not is checked using modulus operator.
If the number is perfectly divisible by 2, test expression number%2 == 0 evaluates to 1 (true) and the number is even.
However, if the test expression evaluates to 0 (false), the number is odd.
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here goes ur answer my dear friend.
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