Write a program to compute and display the sum of the following series:
S = (1 + 2) / (1 * 2) + (1 + 2 + 3) / (1 * 2 * 3) + -------- + (1 + 2 + 3 + ----- + n ) / (1 * 2 * 3 * ----- * n).
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Answer:
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Answered by
1
Answer:
Through C++
Explanation:
#include <iostream.h>
using namespace std;
int main()
{
int n;
int i=1,prod=1,sum=1;
cout<<“enter number:”;
cin>>n;
sum=n(n+1)/2
while(i<=n)
{
prod=i*prod;
i++;
}
float sum1 = sum/prod
cout<<“sum is:”<<sum1;
return 0;
}
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