Question

Write a program to count number between 1 to 100, which are not divisible by 2,3 and 7 in c++

Answer 1

Answer:

Explanation:

#include <iostream>

using namespace std;

int main()

{

   int count=0;

   for(int i=1;i<=100;i++)

   {

       if(i%2!=0&&i%3!=0&&i%7!=0)

       count++;

   }

cout<<count;

   return 0;

}