Question

Write a program to count words not having alphabet 'a' at second position in a string ( any coding language )

Answer 1

C Program to Count Number of Words in a string:

Explanation:

• #include <stdio.h>
• #include <string.h>
• void main()
• {
•    char s[200];
•    int count = 0, i;
•    printf("Enter the string:\n");
•    scanf("%[^\n]s", s);
•    for (i = 0;s[i] != '\0';i++)
•    {
•        if (s[i] == ' ' && s[i+1] != ' ')
•            count++;    
•    }
•    printf("Number of words in given string are: %d\n", count + 1);
• }

Answer 2

Answer:

A C-program to count words not having alphabet 'a' at second position in a string :

#include <stdio.h>

#include <string.h>

int main() {

char sentence[200];

int i;

int counter = 0, word=1;

printf("Enter sentence: ");

fflush(stdin);

fgets(sentence, 500, stdin);

int len = strlen(sentence);

printf( "%s",sentence);

for(i=0;i<len;i++)

{

if(sentence[i]!=' ' && sentence[i+1]==' ')

word=word+1;

}

for (i = 0; sentence[i] !='\0'; i++)

{

if (i==0 && sentence[i+1]=='a')

{

counter = counter +1;

}

if (sentence[i] == ' ' && sentence[i+2] == 'a')

{

counter = counter +1;

}

}

printf("No.of words in the sentence that is having alphabet 'a' at second position is : %d\n", counter);

printf("No.of words in the sentence is : %d\n", word);

printf("No.of words in the sentence that is not having alphabet 'a' at second position is : %d\n", word-counter);

return 0;

}