Question

write a program to display the first n odd number . accept first odd number​

Answer 1

Answer:

Dry Run of the Program

We enter the for loop for(i=1;i<=2*n;i++) where i is your counter. if(i%2==0) it is true as 2%2=0 hence 0==0 so we do not print i and just continue that is skip the below part. if(i%2==0) it is true as 4%2=0 hence 0==0 so we do not print i and just continue that is skip the below part.

Answer 2

Dry run of the program
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