Question

write a program to display the pattern in the output screen
1
10
101
1010
10101
101010
1010101​

Answer 1

Answer:

qrhnwtjeyjw47oqeyj147keq47leq7keyk48l i15i47lwtnwyk wtjwy37kwtneyk qtneukl

mki3rfdfuoakarq4

5inag

Answer 2

The outer loop counter i ranges from 1 to n. i is used to keep track of line number. Line i contains i numbers. So, the inner loop counter j ranges from 1 to i. If j is odd, we print 1, else we print 0.

import java.util.Scanner;

public class Pattern {

   public static void main(String[] args) {

       Scanner scanner = new Scanner(System.in);

       System.out.print("Enter n: ");

       int n = scanner.nextInt();

       for (int i = 1; i <= n; i++) {

           for (int j = 1; j <= i; j++) {

               if (j % 2 == 1) {

                   System.out.print("1 ");

               } else {

                   System.out.print("0 ");

               }

           }

           System.out.println();

       }

   }

}

Enter n: 5

1

1 0

1 0 1

1 0 1 0

1 0 1 0 1