Write a program to enter a 2-digit number and check if the ten's digit is twice the unit's digit.
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Answer:
In Python:
x = input('Enter a 2 digit number: ')
if int(x[0]) == 2 * int(x[1]):
print('Yes')
else:
print('No')
Explanation:
x[0] is the ten's digit. (input() returns a string)
x[1] is the one's digit.
x[0] and x[1] are strings, so we convert them to ints.
int(x[0] == int(x[1])
we want to see if the ten's digit (x[0]) is twice the unit's digit.
int(x[0]) == 2 * int(x[1])
our condition is formed, now we put it in an if-else statement.
if int(x[0]) == 2 * int(x[1]):
print('Yes')
else:
print('No')
If you are doing it in another programming language, try to apply the logic and instructions which I have given.
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