Question

Write a program to enter any 50 numbers and check whether they are divisible by 5 or
not. If divisible then perform the following tasks:
(a) Display all the numbers ending with the digit 5.
(b) Count those numbers ending with 0 (zero).

Answer 1

Answer:

#include <iostream>

using namespace std;

int main()

{

   int n[50], count=0;

   cout<<"Enter 50 numbers\n";

   for(int i=0;i<50;i++)

   {

       cin>>n[i];

   }

   cout<<"Numbers ending with 5 are\n";

   for(int i=0;i<50;i++)

   {

       if(n[i]%5==0)

       {

           if(n[i] % 10 == 5)

           {

               cout<<n[i]<<"\n";

           }

           else

           {

               count++;

           }

       }

   }

   cout<<"There are "<<count<<" numbers ending with zero";

   return 0;

}

Answer 2

Question:-

Write a program to enter any 50 numbers and check whether they are divisible by 5 or

not. If divisible then perform the following tasks:

1. Display all the numbers ending with the digit 5.
2. Count those numbers ending with 0 (zero).

Program:-

This is written in Java.

import java.util.*;

class Number

{

public static void main(String args[])

{

Scanner sc=new Scanner(System.in);

System.out.println("Enter 50 numbers.");

int c=0;

int n[]=new int[50];

for(int i=0;i<50;i++)

{

System.out.print("Enter: ");

n[i]=sc.nextInt();

if(n[i]%10==0)// last digit is zero implies that number is divisible by 5.

c++;

}

System.out.print("Numbers ending with digit 5 are: ");

for(int i=0;i<50;i++)

{

if(n[i]%10==5)

System.out.print(n[i]+" ");

}

System.out.println("Total numbers ending with 0 is: "+c);

}

}