Write a program to enter any sentence and print the number of ‘p’ or ‘P’present in the sentence
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sentence = "Beauty lies in the eyes of beholder";
wordCount = 0;
for i in range(0, len(sentence)-1):
#Counts all the spaces present in the string
#It doesn't include the first space as it won't be considered as a word
if(sentence[i] == ' ' and sentence[i+1].isalpha() and (i > 0)):
wordCount = wordCount + 1;
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