Question

write a program to find number of days between two given days​

Answer 1

PROGRAM

#include<stdio.h>

#include<math.h>

void main()

{

int day1,mon1,year1,day2,mon2,year2;

int ref,dd1,dd2,i;

clrscr();

printf("\nEnter first day, month, year");

scanf("%d%d%d",&day1,&mon1,&year1);

printf("\nEnter second day,month,year");

scanf("%d%d%d",&day2,&mon2,&year2);

ref = year1;

if(year2<year1)

ref = year2;

dd1=0;

dd1=func1(mon1);

for(i=ref;i<year1;i++)

{

if(i%4==0)

dd1+=1;

}

dd1=dd1+day1+(year1-ref)*365;

printf("\nNo. of days of first date fronm the Jan 1 %d= %d",year1,dd1);

/* Count for additional days due to leap years*/

dd2=0;

for(i=ref;i<year2;i++)

{

if(i%4==0)

dd2+=1;

}

dd2=func1(mon2)+dd2+day2+((year2-ref)*365);

printf("\nNo. of days from the reference year's first Jan = %d",dd2);

getch();

}

int func1(x) //x for month y for dd

{ int y=0;

switch(x)

{

case 1: y=0; break;

case 2: y=31; break;

case 3: y=59; break;

case 4: y=90; break;

case 5: y=120;break;

case 6: y=151; break;

case 7: y=181; break;

case 8: y=212; break;

case 9: y=243; break;

case 10:y=273; break;

case 11:y=304; break;

case 12:y=334; break;

default: printf("Error encountered"); exit(1);

}

return(y);

}

Sample Output :

Enter first day, month, year29 7 2009

Enter second day,month,year12 12 2009

No. of days of first date fronm the Jan 1 2009= 210

No. of days from the reference year's first Jan = 346

Answer 2

Explanation:

Just subtract one date from the other. For example if cell A2 has an invoice date in it of 1/1/2015 and cell B2 has a date paid of 1/30/2015, then you could enter use the formula =B2-A2 to get the number of days between the two dates, or 29.