Question

Write a program to find the following series upto n terms:
3,18,83...

Answer 1

Answer:

import java.util.*;

public class Series

{

public static void main(String args[ ])

{

Scanner in=new Scanner (System. in);

int a,c,n;

System.out.println("Enter the value of n");

n=in.nextInt();

for(a=1;a<=n;a++)

{

c=Math.pow(a,4)+2;

System.out.println("The series is ="+c);

}

}

Explanation:

In the given series it is the additive result of 2 with the 4 to the power of the numbers.

Such that,

(1×1×1×1)+2

=1+2

=3

(2×2×2×2)+2

=16+2

=18

(3×3×3×3)+2

=81+2

=83

And vice versa.