Write a program to find the number of trailing zeros (i.e. zeros at the end) in the factorial of 100.
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Answer:
import math
from math import *
the_big_number = str(math.factorial(100))
the_big_list = list(the_big_number)
zeroes = 0
for a in range(int(len(the_big_list)+1)):
current_digit = the_big_list[a]
if(current_digit == '0'):
zeroes += 1
print(zeroes)
Explanation:
i made a list out of the number and looped through it one digit at a time to count the number of zeroes
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