Question

write a program to find the sum of digits of 4 digit number using for loop in c language.​

Answer 1

Answer:

For example, if the input is 98, the variable sum is 0 initially

98%10 = 8 (% is modulus operator, which gives us the remainder when 98 is divided by 10).

sum = sum + remainder

so sum = 8 now.

98/10 = 9 because in C language, whenever we divide an integer by another one, we get an integer.

9%10 = 9

sum = 8 (previous value) + 9

sum = 17

9/10 = 0.

So finally, n = 0, the loop ends; we get the required sum.

Happy new year all of you

Answer 2

The code to execute the given task is as follows:-

#include <stdio.h>

int main() {

   int n;

   scanf("%d", &n);

   

   int copyOfn = n;

   int sumOfDigits = 0;

   for(; copyOfn > 0; copyOfn /= 10) {

       sumOfDigits += (copyOfn %10);

   }

   printf("Sum of digits of %d is %d", n, sumOfDigits);

   

   return 0;

}

• First, we take a 4-digit number as input from the user in variable 'n'.
• We then copy the value 'n' in another variable 'copyOfn'.

• We run a for-loop till the value of copyOfn is greater than 0.

• We then calculate the sum of digits of the n in the for-loop.

• We then print the sum of digits calculated.

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