write a program to find the sum of even and odd numbers in an array.
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Answered by
4
Hey dear,
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/* C Program to find Sum of Even and Odd Numbers in an Array */
#include<stdio.h>
int main()
{
int Size, i, a[10];
int Even_Sum = 0, Odd_Sum = 0;
printf("\n Please Enter the Size of an Array : ");
scanf("%d", &Size);
printf("\nPlease Enter the Array Elements\n");
for(i = 0; i < Size; i++)
{
scanf("%d", &a[i]);
}
for(i = 0; i < Size; i ++)
{
if(a[i] % 2 == 0)
{
Even_Sum = Even_Sum + a[i];
}
else
{
Odd_Sum = Odd_Sum + a[i];
}
}
printf("\n The Sum of Even Numbers in this Array = %d ", Even_Sum);
printf("\n The Sum of Odd Numbers in this Array = %d ", Odd_Sum);
return 0;
}
Hope it will help u...
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/* C Program to find Sum of Even and Odd Numbers in an Array */
#include<stdio.h>
int main()
{
int Size, i, a[10];
int Even_Sum = 0, Odd_Sum = 0;
printf("\n Please Enter the Size of an Array : ");
scanf("%d", &Size);
printf("\nPlease Enter the Array Elements\n");
for(i = 0; i < Size; i++)
{
scanf("%d", &a[i]);
}
for(i = 0; i < Size; i ++)
{
if(a[i] % 2 == 0)
{
Even_Sum = Even_Sum + a[i];
}
else
{
Odd_Sum = Odd_Sum + a[i];
}
}
printf("\n The Sum of Even Numbers in this Array = %d ", Even_Sum);
printf("\n The Sum of Odd Numbers in this Array = %d ", Odd_Sum);
return 0;
}
Hope it will help u...
Answered by
2
Answer:
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int a,s=0,s1=0;
for(int i=0;i<10;i++)
{
cout<<"\nEnter any number";
cin>>a[i];
}
for(i=0;i<10;i++)
{
if(a[i]%2==0)
s=s+a[i];
else
s1=s1+a[i];
}
cout<<"\nSum of odd numbers is<<s1;
cout<<"\nSum of even numbers is<<s;
getch();
}
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