Question

#write a program to find the value of (sin^3 A +sin^3 B)/(cos^2 A + sin^2 B).​

Answer 1

Answer:

sinA+sin

2

A+sin

3

A=1

sinA+sin

3

A=1−sin

2

A=cos

2

A

sinA(1+sin

2

A)=cos

2

A

sinA(2−cos

2

A)=cos

2

A (since, sin

2

A=1−cos

2

A)

Squaring both sides,

sin

2

A(4−4cos

2

A+cos

4

A)=cos

4

A

(1−cos

2

A)(4−4cos

2

A+cos

4

A)=cos

4

A

4−4cos

2

A+cos

4

A−4cos

2

A+4cos

4

A−cos

6

A=cos

4

A

4−cos

6

A+4cos

4

A−8cos

2

A=0

cos

6

A−4cos

4

A+8cos

2

A=4