Write a program to input 10 no.s and print the first digit of all 3- digit no. using while loop c++
Answers
Answered by
1
Answer:
Explanation:
#include<iostream>
using namespace std;
int main()
{
int n=10,sum=0,number;
cout<<"\n Enter numbers:";
while(n>0)
{
cin>>number;
sum+=number;
n--;
}
if(number>99 && number<1000)
cout<<"number"
return 0;
}
Answered by
2
Answer:
#include <iostream>
using namespace std;
int main()
{
int arr[10];
cout << "Enter all 10 numbers- \n";
for(int i = 0; i < 10; i++){
cin >> arr[i];
}
int i = 0;
while(i < 10){
if(arr[i] >= 100 && arr[i] <= 900){
cout << arr[i] << " is a 3 digit number and the first digit is " << (int)arr[i]/100 << "\n";
}
i++;
}
return 0;
}
Explanation:
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