Write a program to input 10 numbers into an integer array and print those single-digit positive numbers which are not present in the
array
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1
Answer:
#include <iostream>
using namespace std;
int main()
{
int i,array[10],sum=0;
cout<<"Enter 10 elements :";
for (i = 0; i < 10; ++i)
{
cin >> array[i];
}
for (i = 0; i < 10; ++i)
{
sum = sum + array[i];
}
cout<< "Sum of numbers is : " << sum;
return 0;
}
Explanation:
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