write a program to
input 3 numbers and display the largest number / smaller number.
Answers
follow me ti be followed back
Example 1: Using if Statement
#include <stdio.h>
int main() {
double n1, n2, n3;
printf("Enter three different numbers: ");
scanf("%lf %lf %lf", &n1, &n2, &n3);
// if n1 is greater than both n2 and n3, n1 is the largest
if (n1 >= n2 && n1 >= n3)
printf("%.2f is the largest number.", n1);
// if n2 is greater than both n1 and n3, n2 is the largest
if (n2 >= n1 && n2 >= n3)
printf("%.2f is the largest number.", n2);
// if n3 is greater than both n1 and n2, n3 is the largest
if (n3 >= n1 && n3 >= n2)
printf("%.2f is the largest number.", n3);
return 0;
}
Example 2: Using if...else Ladder
#include <stdio.h>
int main() {
double n1, n2, n3;
printf("Enter three numbers: ");
scanf("%lf %lf %lf", &n1, &n2, &n3);
// if n1 is greater than both n2 and n3, n1 is the largest
if (n1 >= n2 && n1 >= n3)
printf("%.2lf is the largest number.", n1);
// if n2 is greater than both n1 and n3, n2 is the largest
else if (n2 >= n1 && n2 >= n3)
printf("%.2lf is the largest number.", n2);
// if both above conditions are false, n3 is the largest
else
printf("%.2lf is the largest number.", n3);
return 0;
}
Example 3: Using Nested if...else
#include <stdio.h>
int main() {
double n1, n2, n3;
printf("Enter three numbers: ");
scanf("%lf %lf %lf", &n1, &n2, &n3);
if (n1 >= n2) {
if (n1 >= n3)
printf("%.2lf is the largest number.", n1);
else
printf("%.2lf is the largest number.", n3);
} else {
if (n2 >= n3)
printf("%.2lf is the largest number.", n2);
else
printf("%.2lf is the largest number.", n3);
}
return 0;
}
The output of all these programs above will be the same.
Enter three numbers: -4.5
Enter three numbers: -4.53.9
Enter three numbers: -4.53.95.6
Enter three numbers: -4.53.95.65.60 is the largest number