Question

Write a program to input a number. Usingwhile loopperform the followingin one single program.
a.Find the number of digits in input
b.Display all the digits in new line
c.Check whether there are even no.of digits or odd no.of digits in input
d.Find the sum of digitsSample
Input : 372
Sample Output : 3
digitsDigits in input are: 372
The given input has odd no.of digits.Sum of digits = 12

Answer 1

$\huge\red{\mid{\fbox{\tt{Using\: Python\: 3}}\mid}}$

digits = list(map(int, str((n := int(input("n: "))))))

digits_len = len(digits)

print("No of digits:", digits_len, "\n")

print("Digits:\n" + "\n".join(list(map(str, digits))), "\n")

print("Even digits\n") if digits_len % 2 == 0 else print("Odd digits\n")

print("Sum:", sum(digits))

$\large\mathsf\color{lightgreen}useful?\: \color{white}\longrightarrow\: \color{orange}brainliest!$

Answer 2

Answer:

digits = list(map(int, str((n := int(input("n: "))))))

digits_len = len(digits)

print("No of digits:", digits_len, "\n")

print("Digits:\n" + "\n".join(list(map(str, digits))), "\n")

print("Even digits\n") if digits_len % 2 == 0 else print("Odd digits\n")

print("Sum:", sum(digits))

\large\mathsf\color{lightgreen}useful?\: \color{white}\longrightarrow\: \color{orange}brainliest!