Write a program to input a sentence and print those words which do not contain a
vowel. Also count those words.
Write a program
Answers
Explanation:
# include <stdio.h>
int main()
{
char line[150];
int vowels, consonant, digit, space;
vowels = consonant = digit = space = 0;
printf("Enter a line of string: ");
fgets(line, sizeof(line), stdin);
for (int i = 0; line[i] != '\0'; ++i)
{
if (line[i] == 'a' || line[i] == 'e' || line[i] == 'i' || line[i] == 'o' || line[i] == 'u' || line[i] == 'A' || line[i] == 'E' || line[i] == 'I' || line[i] == 'O' || line[i] == 'U')
{
++vowels;
}
else if ((line[i] >= 'a' && line[i] <= 'z') || (line[i] >= 'A' && line[i] <= 'Z')) { ++consonant;
} else if (line[i] >= '0' && line[i] <= '9') { ++digit; } else if (line[i] == ' ')
{
++space;
}
}
printf("Vowels: %d", vowels);
printf("\nConsonants: %d", consonant);
printf("\nDigits: %d", digit);
printf("\nWhite spaces: %d", space);
return 0;
}