Question

write a program to input length and breadth of a rectangle . calculate and display the area, perimeter or diagonal of the rectangle as per the users choice​

Answer 1

Answer:

Import java.util.*;

public class rectangle

{

public static void main()

{

Scanner sc =new Scanner (System.in);

System.out.println("enter length,breadth of rectangle");

double l=sc.nextDouble();

double b=sc.nextDouble ();

System.out.println ("enter choice");

int ch=sc. nextInt();

switch(ch)

{

case1:

double a;

a=l*b;

System.out.println ("area="+a);

break;

}

case 2:

{

double p;

p=2*(l+b);

System. out.println ("perimeter="+p);

break;

}

case 3:

{

double d=Math.sqrt(l*l+b*b);

System. out.println ("diagonal="+d);

break;

}

default :

{

System.out.println ("wrong choice");

}

}

}

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs

Answer 2

choice = "Yes"

while choice == "Yes":

   l = float(input("Enter the length of the rectangle: "))

   b = float(input("Enter the breadth of the rectangle: "))

   print("Would you like to find:", "1. The area", "2. The perimeter", "3. The diagonal", sep = "\n")

   op = int(input("Enter the number of choice of operation: ") )

   if op == 1:

       area = l*b

       print(area, "is the area of the rectangle.")

   elif op == 2:

       pm = 2*(l + b)

       print(pm, "is the perimeter of the rectangle.")

   elif op == 3:

       dg = (l**2 + b**2)**(1/2)

       print(dg, "is the diagonal of the rectangle.")

   print()

   choice = input("Would you like to go again? [Yes/No]: ")