Question

Write a program to multiply two 1 byte hex numbers stored in D030 H and D031 H. Store the result in
next consecutive memory location. ​

Answer 1

Answer:

Explanation:Multiply two 8 bit numbers stored at address 2050 and ... the result to HL; DCR C decreaments C by 1; JNZ 200A jumps program counter to 200A if zero flag = 0; SHLD stores value of H at memory location 3051 and L at 3050 ... next: Assembly language program (8085 microprocessor) to add two ...

Answer 2

Answer:

To write a program that multiplies two 1-byte hex numbers stored in memory, we need to follow a set of instructions that will accomplish the task. The steps we will take are as follows:

• Load the first 1-byte hex number from memory location D030 H into a register.
• Load the second 1-byte hex number from memory location D031 H into another register.
• Multiply the two numbers using a multiplication instruction and store the result in a third register.
• Store the result in the next consecutive memory location.

Here's the program in assembly language:

LD A, (D030H)   ; Load first number into register A

LD B, (D031H)   ; Load second number into register B

MUL             ; Multiply the two numbers and store the result in register pair HL

LD (D032H), HL  ; Store the result in the next consecutive memory location

In the above program, we first load the first number from memory location D030 H into register A using the LD instruction. Similarly, we load the second number from memory location D031 H into register B using the LD instruction.

Next, we use the MUL instruction to multiply the two numbers and store the result in register pair HL. Finally, we use the LD instruction to store the result in the next consecutive memory location, which is D032 H.

Learn more about assembly language:

https://brainly.in/question/5563872
#SPJ2