write a program to print factorial value of no. from 100-200
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Explanation:
C program to find factorial of a number
long factorial(int);
int main() { int n;
printf("Enter a number to calculate its factorial\n"); scanf("%d", &n);
printf("%d! = %ld\n", n, factorial(n));
return 0; }
long factorial(int n) { int c; long r = 1;
for (c = 1; c <= n; c++) r = r * c;
return r; }
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Answer:
Given an integer n, find the number of digits that appear in its factorial, where factorial is defined as, factorial(n) = 1*2*3*4……..*n and factorial(0) = 1
Examples :
Input : n = 1 Output : 1 1! = 1 , hence number of digits is 1 Input : 5 Output : 3 5! = 120, i.e., 3 digits Input : 10 Output : 7 10! = 3628800, i.e., 7 digits
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