Question

write a program to print the factor of 10​

Answer 1

$\texttt{\textsf{\large{\underline{The C{o}de}:}}}$

The given problem is solved using language - Java.

public class Factors_Of_10{

   public static void main(String s[]){

       System.out.print("Factors of 10 are: ");

       for(int i=1;i<=10;i++){

           if(10%i==0)

               System.out.print(i+" ");

       }

   }

}

$\texttt{\textsf{\large{\underline{Explanation}:}}}$

• Line 1: Class declaration.
• Line 2: Method declaration. Starting point of execution of this program.
• Line 3: Prints a message.
• Line 4 - 7: Here, a loop iterates in range 1 to 10. If any number in this range divides 10, then it is displayed.
• Line 8: End of main().
• Line 9: End of class.

$\texttt{\textsf{\large{\underline{O{u}tput}:}}}$

Factors of 10 are: 1 2 5 10

See attachment for verification.

Answer 2

Answer:

Program In Java:-

Using Do while loop:-

public class Main

{

public static void main(String args[])

{

int n=10,i=1;

System.out.println("Factors of 10 are:");

do

{

if(n%i==0)

System.out.print(i+" ");

i++;

}

while(i<=10);

}

}

Using for loop:-

public class Main

{

public static void main(String args[])

{

int n=10,i=1;

System.out.println("Factors of 10 are:");

for( i=1;i<=10;i++)

{

if(n%i==0)

System.out.print(i+" ");

}

}

}

Using while loop:-

public class Main

{

public static void main(String args[])

{

int n=10,i=1;

System.out.println("Factors of 10 are:");

while(i<=10)

{

if(n%i==0)

System.out.print(i+" ");

i++;

}

}

}

Logic:-

• Run a loop upto 10 if(n%i==0) means if I at any iteration is divisible by i it prints i (means it's factor).