Computer Science, asked by debkotatoyanatha, 1 month ago

Write a program to print the first ten natural numbers .(use forNEXT)​

Answers

Answered by rohithrvs4
0

Answer:

#include <stdio.h>

void main()

{

int i;

printf("The first 10 natural numbers are:\n");

for (i=1;i<=10;i++)

{

printf("%d ",i);

}

printf("\n");

}

Answered by gnulinuxbsduser
0

Answer:

python -->

print("here are the first ten natural numbers ==>\n")

i = 0

while (i < 10):

       i += 1

       print(i)

c -->

//compiled on gcc linux 5.12

//to compile it on linux type gcc program.c -o program_naturalnum

#include <stdio.h>

int main()

{

printf("natural numbers from 1 to 10\n");

int i;

for (i = 1; i < 11; i++){

 printf("%d\n", i);

}

return 0;

}

java -->

//Main.java

public class Main {

  public static void main(String[] args) {

for (int i = 1; i < 10; i++) {

   System.out.println(i);

}

 }

}

c++ -->

#include <iostream>

int main()

{

std::cout << "natural numbers from 1 to 10\n" << std::endl;

int i;

for (i = 1; i < 11; i++){

 std::cout << i << std::endl;

}

return 0;

}

fortran -->

program NatNUM

integer i

 do i = 0, 9

    j = i+1

    print*, j

 end do

end program NatNUM

cobol ->

PROGRAM-ID. NATNUM.

ENVIRONMENT DIVISION.

CONFIGURATION SECTION.

DATA DIVISION.

FILE SECTION.

WORKING-STORAGE SECTION.

01 Ind PIC 9(1) VALUE 0.

PERFORM DIVISON.

PERFORM OutputData WITH TEST AFTER UNTIL Ind > 10

      GO TO ForLoop

OutputData.

      DISPLAY Ind.

      ADD 1 TO Ind.

ForLoop.

      PERFORM OutputData2 VARYING Ind FROM 1 BY

      1 UNTIL Ind = 10

      STOP RUN.

OutputData2.

      DISPLAY Ind.

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