Question

Write a program to show the square of first 10 natural numbers

Answer 1

Answer:

The sum of squares of the first n natural numbers is found by adding up all the squares.

Input - 5

Output - 55

Explanation - 12 + 22 + 32 + 42 + 52

There are two methods to find the Sum of squares of first n natural numbers −

Using Loops − the code loops through the digits until n and find their square, then add this to a sum variable that outputs the sum.

Example#include <iostream> using namespace std; int main() {    int n = 5;    int sum = 0;    for (int i = 1; i >= n; i++)       sum += (i * i);    cout <<"The sum of squares of first "<<n<<" natural numbers is "<<sum;    return 0; }OutputThe sum of squares of first 5 natural numbers is 55

Using Formula − To decrease the load on the program you can use mathematical formula to find the sum of squares on first n natural numbers. The mathematical formula is : n(n+1)(2n+1)/6

Example#include <stdio.h> int main() {    int n = 10;    int sum = (n * (n + 1) * (2 * n + 1)) / 6;    printf("The sum of squares of %d natural numbers is %d",n, sum);    return 0; }OutputThe sum of squares of 10 natural numbers is 385

Answer 2

Answer:

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