write a program to solve c=a²+b² in c++
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Answer:
You have an inbuilt function called pow(a,b) which returns the value of a^b (a to the power of b).
So answer for your question is pow(a,2) == pow(b,2) + pow(c,3) ;
Or simply you could write a*a == b*b + c*c*c ;
Note: I have used == assuming you needed to compare LHS and RHS.
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Language:
C++
Program:
#include <iostream>
using namespace std;
int main(){
int a,b,c;
cout<<"Enter the value of a: ";
cin>> a;
cout << "Enter the value of b: "
cin>> b;
cout<< "The required value of c is : ";
cout<< (a*a)+(b*b);
return 0;
}
Output:
Consider the attachment.
Explanation:
- Took input for a and b.
- and printed the sum after multiplying them to themselves.
Attachments:
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