Question

WRITE A PROGRAM USNG WHILE LOOP TO REVERSE THE DIGITS OF THE NUMBER.
Hint : use the modulus operator to extract the last digit and the integer division by 10 to get the n-1 digit number from the n digit number.
NO IS - 12345
ANS IS 54321

Answer 1

Answer:

Using Python:

starting_number = 12345

number = starting_number

ending_number = 0

while (number > 0):

   remainder = number % 10  

   ending_number = (ending_number * 10) + remainder  

   number = number // 10

print(f"Starting number: {starting_number}")

print(f"Ending number: {ending_number}")

print("Starting number: " + starting_number)

print("Ending number: " + ending_number)

Explanation:

You didn't specify what language you were using, so I'll be using Python. We'll have a look at this a line at a time. You can have a look at the image attached to see how the numbers change

First we need to set up our variables.

starting_number will be the number printed at the end.

> starting_number = 12345

number will be used in our while loop.

> number = starting_number

ending_number will be our final answer.

> ending_number = 0

Now we initialize our while loop

While the given number variable is more than 0. (don't forget: number = starting_number)

> while (number > 0):

   Using the modulus operator, you can get the number at the end of your starting_number variable.

>     remainder = number % 10

   Multiply your ending number by ten and add the remainder variable above.

>     ending_number = (ending_number * 10) + remainder

    Finally, divide your number variable by ten to do your next number

>     number = number // 10

Printing

Once our while loop is complete, when number <= 0, we can finally print our answer.

> print(f"Starting number: {starting_number}")

> print(f"Ending number: {ending_number}")