Question

write a program which accepts 10 integers in an array and then arrange the array in ascending order.

Answer 1

#include <iostream>
using namespace std;
#define MAX 100
int main()
{
//array declaration
int arr[MAX];
int n,i,j;
int temp;
//read total number of elements to read cout<<"Enter total number of elements to read: ";
cin>>n;
//check bound
if(n<0 || n>MAX)
{ cout<<"Input valid range!!!"<<endl; return -1; }
//read n elements for(i=0;i<n;i++) { cout<<"Enter element ["<<i+1<<"] "; cin>>arr[i]; }
//print input elements
cout<<"Unsorted Array elements:"<<endl; for(i=0;i<n;i++)
cout<<arr[i]<<"\t"; cout<<endl;
//sorting - ASCENDING ORDER for(i=0;i<n;i++) {
for(j=i+1;j<n;j++)
{ if(arr[i]>arr[j]) { temp =arr[i]; arr[i]=arr[j]; arr[j]=temp; } } }
//print sorted array elements cout<<"Sorted (Ascending Order) Array elements:"<<endl; for(i=0;i<n;i++)
cout<<arr[i]<<"\t";
cout<<endl;
return 0; }

Answer 2

The program in java
class SelectionSort{//class declarationpublic void main(){//method declaration  int a[]={1,6,9,8,3,2,5,7,4,10};  int size=a.length;  int i,j,small,tmp,pos;  for(i=0;i<size;i++)  {//i loop start    small=a[i];    pos=i;    for(j=i+1;j<size;j++)    {//j loop start        if(a[j]<small)        {            small=a[i];            pos=j;        }    }//j loop end    tmp=a[i];    a[i]=a[pos];    a[pos]=tmp;}//i loop end}//method end}//class end