Computer Science, asked by trashikagoyal, 7 months ago

Write a program which takes a string (maximum 80 characters) terminated by a full stop. The words in this string are assumed to be separated by one or more blanks. Arrange the words of the input string in descending order of their lengths. Same length words should be sorted alphabetically. Each word must start with an uppercase letter and the sentence should be terminated by a full stop.

Answers

Answered by saivinay2008
5

Answer:

INPUT :

“ This is human resource department ”

OUTPUT :

Department Resource Human This is.

INPUT :

“To handle yourself use your head and to handle others use your heart.”

OUTPUT :

Yourself Handle Handle Ohers Heart Head Your Your And Use Use To To.

Explanation:

import java.util.*;

public class prog1_2005

{

public static void main(String ar[])

{

Scanner sc=new Scanner(System.in);

System.out.println(“enter the string”);

String str=sc.nextLine();

str=str.trim();

str=str.replaceAll(“\\s+”,” “);

int l=str.length();

if(str.charAt(l-1)==’.’&&l<=80)

{

str=str.substring(0,l-1)+” “;

int i,j,c=0,temp;

String temp1;

String a[]=str.split(” “);

int b[]=new int[a.length];

for(i=0;i<a.length;i++)

{

b[i]=a[i].length();

a[i]=Character.toUpperCase(a[i].charAt(0))+a[i].substring(1);

}

for(i=0;i<b.length;i++)

{

for(j=0;j<b.length-1;j++)

{

if(b[j]<b[j+1])

{

temp=b[j];

b[j]=b[j+1];

b[j+1]=temp;

temp1=a[j];

a[j]=a[j+1];

a[j+1]=temp1;

}

}

}

for(i=0;i<a.length-1;i++)

{

if(a[i].length()==a[i+1].length())

{

if(a[i].compareTo(a[i+1])>0)

{

temp1=a[i];

a[i]=a[i+1];

a[i+1]=temp1;

}

}

}

String st=””;

for(i=0;i<a.length;i++)

{

st=st+a[i]+” “;

}

st=st.substring(0,l-1)+’.’;

System.out.println(st);

}

}

}

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