Question

Write a program which will display a message:
1."Hi",if a particular entered value is equal to 1.
2."Hello",if a particular entered value is equal to 2.
3."No match found",if none of the conditions are matching

Answer 1

Answer:

import Java. until.*;

public class Display

{

public static void main ()

{

Scanner sc = me new Scanner (system.in)

int n ;

System.out.println ("ENTER YOUR choose");

n= sc.nextInt

Switch (n)

{

case1:

System.out.println ("Hi");

break ;

case 2

System.out.println ("Hello ");

break ;

default:

System.out.println ("no match found");

}

}

}

Answer 2

Answer:

This is the required program for the question. See the attachment for output.

1. In Java.

import java.util.*;

public class Java {

public static void main(String[] args) {

int n;

Scanner sc=new Scanner(System.in);

System.out.print("Enter a number: ");

n=sc.nextInt();

if(n==1)

System.out.print("Hi.");

else if(n==2)

System.out.print("Hello.");

else

System.out.print("Invalid Number.");

sc.close();

}

}

2. In Python.

n=int(input("Enter a number: "))

if n==1:

print("Hi.")

elif n==2:

print("Hello.")

else:

print("Invalid Number.")

3. In C.

#include <stdio.h>

void main() {

int n;

printf("Enter a number: ");

scanf("%d", &n);

if(n==1)

printf("Hi.");

else if(n==2)

printf("Hello.");

else

printf("Invalid Number.");

}

4. In C++

#include <iostream>

using namespace std;

int main() {

int n;

cout << "Enter a number: ";

cin >> n;

if(n==1)

cout << "Hi.";

else if(n==2)

cout << "Hello.";

else

cout << "Invalid Number.";

return 0;

}

Steps To Solve:

1. Ask the user to enter a number.
2. If the number is 1, display "Hi".
3. If the number is 2, display "Hello".
4. If the number is neither 1 nor 2, display the message that says - "Invalid Input".

See the attachment for output ☑.